0.5x^2=1

Solution for 0.5x^2=1 equation:

0.5x^2=1

We move all terms to the left:

0.5x^2-(1)=0

a = 0.5; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·0.5·(-1)
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2}}{2*0.5}=\frac{0-\sqrt{2}}{1}
=-\frac{\sqrt{}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2}}{2*0.5}=\frac{0+\sqrt{2}}{1}
=\frac{\sqrt{}}{1}
$